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What is the number of rounds that a wheel of diameter $\frac{5}{11}m will make in traversing 7 km?

A3300

B3500

C4400

D4900

Answer:

D. 4900

Read Explanation:

Solution:

Distance=Circumference×No.ofRevolutionDistance=Circumference\times{No.of Revolution}

Distance = 7 km

Diameter=511mDiameter =\frac{5}{11}m

Radius=5112Radius=\frac{\frac{5}{11}}{2}

Radius,r=522Radius,r=\frac{5}{22}

Circumference of Wheel = 2πr2\pi{r}

=2×227×522= 2\times{\frac{22}{7}}\times{\frac{5}{22}}

=107=\frac{10}{7}

7km=107×No.ofRevolution7km=\frac{10}{7}\times{No.of Revolution}

No.ofRevolution=710×1000No.of Revolution=\frac{7}{10}\times{1000}

=4900=4900


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