Zeros of p(x)=x2−27p(x) = x^2-27p(x)=x2−27are: A±9√3B3√3C±7√3DNone of theseAnswer: B. 3√3 Read Explanation: p(x)=x2−27=0p(x) = x^2-27=0p(x)=x2−27=0x2=27x^2=27x2=27x=±27x=±\sqrt{27}x=±27=±33=±3\sqrt3=±33 Read more in App
