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The area of the ring between two concentric circles, whose circumference are 88 cm and 132 cm, is :

A780

B770

C715

D660

Answer:

B. 770

Read Explanation:

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According to question,

Circumference of outer circle =2πr=132cm= 2\pi{r} = 132 cm

r=1322×22×7=21cmr=\frac{132}{2\times{22}}\times{7}=21cm

Circumference of inner circle =2πr1=88cm= 2\pi{r_1} = 88cm

r1=882×22×7=14cmr_1=\frac{88}{2\times{22}}\times{7}=14 cm

Area of outer circle =πr2= \pi{r^2}

=227×21×21=\frac{22}{7}\times{21}\times{21}

=1386cm2=1386cm^2

and Area of inner circle =πr12=\pi{r^2_1}

=227×14×14=\frac{22}{7}\times{14}\times{14}

=616cm2=616cm^2

Area of ring =1386616=770cm2=1386-616=770cm^2


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