Let the length of sides of the two triangles be a1 and a2 respectively and their altitudes be h1 and h2 respectively.
Then, ⇔43a2243a12=3625
a22a12=3625
a2a1=65
and.,
21×a1×h121×a1×h1=3625
6h25h1=3625
h2h1=65
AltitudeRatio h1: h2 = 5 : 6