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The area of two equilateral triangles are in the ratio 25 : 36. Their altitudes will be in the ratio :

A25 : 36

B36 : 25

C\sqrt{5}$ : $\sqrt{6}

D5 : 6

Answer:

D. 5 : 6

Read Explanation:

Let the length of sides of the two triangles be a1 and a2 respectively and their altitudes be h1 and h2 respectively.

Then, ⇔34a1234a22=2536\frac{\frac{\sqrt{3}}{4}a1^2}{\frac{\sqrt{3}}{4}a2^2}=\frac{25}{36}

a12a22=2536\frac{a1^2}{a2^2}=\frac{25}{36}

a1a2=56\frac{a1}{a2}=\frac{5}{6}

and.,

12×a1×h112×a1×h1=2536\frac{\frac{1}{2}\times{a1}\times{h1}}{\frac{1}{2}\times{a1}\times{h1}}=\frac{25}{36}

5h16h2=2536\frac{5h1}{6h2}=\frac{25}{36}

h1h2=56\frac{h1}{h2}=\frac{5}{6}

AltitudeRatio h1: h2 = 5 : 6


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