ADisplacement
BVelocity
CAcceleration
DForce
Answer:
A. Displacement
Read Explanation:
Velocity-Time Graph Mechanics
The area enclosed between the velocity-time (v-t) graph and the time axis is numerically equal to the displacement (or total distance, if velocity is strictly positive) covered by the object during a specific time interval.
Mathematical Basis: The unit of the area can be derived as: (Velocity units) × (Time units) = (m/s) × (s) = meters (m). Since the unit of displacement is meters, the area represents displacement.
Graph Interpretation:
If the object moves with uniform velocity, the graph is a straight line parallel to the time axis. The area under this graph forms a rectangle, where Area = velocity × time.
If the object moves with uniform acceleration starting from rest, the graph is a straight line passing through the origin. The area forms a triangle, where Area = 0.5 × base × height.
For non-uniform motion, the area is calculated using integration: s = ∫v dt.
Slope of v-t graph represents acceleration.
Area under v-t graph represents displacement.
Slope of position-time (x-t) graph represents velocity.
