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The areas of a square and a rectangle are equal. The length of the rectangle is greater than the length of any side of the square by 5 cm and the breadth is less by 3 cm. Find the perimeter of the rectangle.

A17 cm

B26 cm

C30 cm

D34 cm

Answer:

D. 34 cm

Read Explanation:

areas of a square and a rectangle are equal.

a2=L×Ba^2=L\times{B}

length of the rectangle is greater than the length of any side of the square by 5 cm and breadth is less by 3 cm

L=a+5L=a+5

B=a3B=a-3

a2=(a+5)×(a3)a^2=(a+5)\times{(a-3)}

a2=a23a+5a15a^2=a^2-3a+5a-15

2a=152a=15

a=152a=\frac{15}{2}

L=152+5=252L=\frac{15}{2}+5=\frac{25}{2}

B=1523=92B=\frac{15}{2}-3=\frac{9}{2}

Perimeter of Rectangle = 2(L+B)2(L+B)

=2(252+92)=2(\frac{25}{2}+\frac{9}{2})

=2×342=2\times{\frac{34}{2}}

=34cm=34cm


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