A1988
B1990
C1992
D1993
Answer:
D. 1993
Read Explanation:
The calendar for the year 1982 is the same as for the year 1993.
A standard calendar repeats when the total number of odd days (extra days beyond complete weeks) accumulates to a multiple of 7.
A normal year (365 days) has 1 odd day (365 ÷ 7 leaves a remainder of 1).
A leap year (366 days) has 2 odd days (366 ÷ 7 leaves a remainder of 2).
Let's count the odd days starting from 1982 until the sum is perfectly divisible by 7:
1982 (Normal) = 1 odd day
1983 (Normal) = 1 odd day
1984 (Leap) = 2 odd days
1985 (Normal) = 1 odd day
1986 (Normal) = 1 odd day
1987 (Normal) = 1 odd day
1988 (Leap) = 2 odd days
1989 (Normal) = 1 odd day
1990 (Normal) = 1 odd day
1991 (Normal) = 1 odd day
1992 (Leap) = 2 odd days
Total Odd Days = 1 + 1 + 2 + 1 + 1 + 1 + 2 + 1 + 1 + 1 + 2 = 14 days.
Since 14 is exactly divisible by 7 (14 ÷ 7 = 2 weeks, with 0 remainder), the calendar resets perfectly. Therefore, the very next year, 1993, will have an identical calendar to 1982.