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The compound interest on a sum at 18% p.a. for 1 ½ years, compounded yearly, is ₹2 862. Find the principal.

A₹10,000

B₹8,000

C₹2,000

D₹4,000

Answer:

A. ₹10,000

Read Explanation:

For (112)(1\frac{1}{2}) years compounded yearly:

  • Interest for the first 1 year is compounded.

  • For the remaining (12)( \frac{1}{2} ) year, simple interest is calculated on the amount after 1 year.

Let the principal be (P).

After 1 year at (18%):

Amount=P(1+18100)=1.18P\text{Amount} = P\left(1+\frac{18}{100}\right)=1.18P

For the next half-year:

Interest=1.18P×18100×12\text{Interest} = 1.18P \times \frac{18}{100} \times \frac12
=1.18P×0.09=1.18P \times 0.09
=0.1062P=0.1062P

So total amount after (112)(1\frac12) years:

1.18P+0.1062P=1.2862P1.18P + 0.1062P = 1.2862P

Compound interest:

1.2862P−P=0.2862P1.2862P - P = 0.2862P

Given:

0.2862P=28620.2862P = 2862
P=28620.2862P = \frac{2862}{0.2862}
P=10,000P = 10,000

=₹10,000


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