Question

The diagonal of a square A is (a+b). The diagonal of a square whose area is twice the area of square A, is

• A. 2 (a+b)
• B. $$2 (a+b)^2$$
• C. $$\sqrt{2}(a+b)$$
• D. $$\sqrt{2}(a-b)$$

Answer 1

Answer:

$$\sqrt{2}(a+b)$$

Area of the square A $=\frac{(diagonal)^2}{2}$

$=\frac{(a+b)^2}{2}$

Area of the new square $==\frac{(a+b)^2}{2}\times{2}=(a+b)^2$

=>Side=(a+b)

$Diagonal=\sqrt{2}\times{side}$

$=\sqrt{2}(a+b)$