Question

The diameter of circle is $\frac{7}{4}$ times the base of triangle, and the height of triangle is 14cm.If the area of the triangle is 56cm², then what is the circumference of the circle?(use $\pi=\frac{22}{7})$

• A. 22 cm
• B. 44 cm
• C. 40 cm
• D. 11 cm

Answer 1

Answer:

B. 44 cm

diameter of circle is $\frac{7}{4}$ times the base of triangle

$D=\frac{7}{4}(base)$

$r=\frac{\frac{7}{4}(Base)}{2}$

$r=\frac{7}{8}(Base)$

$Base=\frac{8r}{7}$

height of triangle is 14cm

$h=14cm$

area of the triangle is 56cm²

$Area = \frac{1}{2}\times{Base}\times{height}$

$56=\frac{1}{2}\times{\frac{8r}{7}}\times{14}$

$r=7cm$

Circumference of circle $=2\pi{r}$

$=2\times{\frac{22}{7}}\times{7}$

$=44cm$