Challenger App

No.1 PSC Learning App

1M+ Downloads
The equation x²-6x+9=0 can be written as:

A(x+3)2=0(x + 3)^2 = 0

B(x3)2=0(x-3)^2 = 0

C(x2)(x3)2=0(x-2)(x-3)^2 = 0

D(x2)(x3)=0(x-2)(x-3) = 0

Answer:

(x3)2=0(x-3)^2 = 0

Read Explanation:

(x3)2=0(x-3)^2 = 0


Related Questions:

Let x2+y22a(x+y)+a2=0x^2+y^2-2a (x+y)+a^2=0 be an equation of a circle. Then

image.png

The roots of the equation ax2+bx+c=0ax^2+ bx + c = 0 are equal if:

image.png
Solve: 2(5x - 3) + 3(3x - 5) = 93