Question

The equivalent length of a column as per Euler's theory whose one end is fixed and the other end is hinged is given by

• A. L
• B. L/2
• C. 2L
• D. L/√2

Answer 1

Answer:

D. L/√2

End conditions	$L_e$	Buckling load
Both ends Hinged	$L_e=L$	$P_b=\frac{\pi^2EI}{L^2}$
Both ends Fixed	$L_e=\frac L2$	$P_b=\frac{4\pi^2EI}{L^2}$
One end fixed and other end is free	$L_e=2L$	$P_b=\frac{\pi^2EI}{4L^2}$
One end fixed and other end is hinged	$L_e=\frac {L}{\sqrt2}$	$P_b=\frac{2\pi^2EI}{L^2}$