In the Euler's crippling load, the column which has both ends fixed is _______________times of the column which has both ends hinged.

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In the Euler's crippling load, the column which has both ends fixed is _______________times of the column which has both ends hinged.

Atwo

Bthree

Cfour

Dsix

Answer:

C. four

Read Explanation:

The crippling load of a column with both ends fixed is four times that of a column with both ends hinged. This can be calculated using Euler's column formula and effective length equation. The ratio of the crippling loads is equal to the square of the effective length for both end hinged divided by both ends fixed, which is equal to 4.

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Match List-I (End conditions of columns) with List-ll (Equivalent length in terms of hinged-hinged column) and select the correct answer using the codes given below the lists

	List I		List II
a	Both ends Hinged	1	$L_e=L$
d	One end fixed and other end is free	2	$L_e=\frac {L}{\sqrt2}$
c	One end fixed and other end is hinged	3	$L_e=\frac L2$
d	Both ends Fixed	4	$L_e=2L$