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The equivalent length of the column when both the ends are fixed is

AL

BL/2

CL/4

D2L

Answer:

B. L/2

Read Explanation:

End conditions

LeL_e

Buckling load

Both ends Hinged

Le=LL_e=L

Pb=π2EIL2P_b=\frac{\pi^2EI}{L^2}

Both ends Fixed

Le=L2L_e=\frac L2

Pb=4π2EIL2P_b=\frac{4\pi^2EI}{L^2}

One end fixed and other end is free

Le=2LL_e=2L

Pb=π2EI4L2P_b=\frac{\pi^2EI}{4L^2}

One end fixed and other end is hinged

Le=L2L_e=\frac {L}{\sqrt2}

Pb=2π2EIL2P_b=\frac{2\pi^2EI}{L^2}


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