Let the two numbers be 11x and 11y (since HCF = 11).
Sum=132
11x+11y=132⇒x+y=12
Both numbers are greater than 42
11x > 42 \Rightarrow x \ge 4,\quad 11y > 42 \Rightarrow y \ge 4
(x) and (y) must be coprime (because HCF is exactly 11)
Possible coprime pairs with sum 12:
(1, 11) (too small)
(5, 7) ✅
(7, 5)
11×5=55,11×7=77
Difference:
77−55=22