Question

The marks of A is 62% more than B. If the marks of A is decreased by 24, then his marks becomes 150% of the marks of B. Find the marks of A.

• A. 280
• B. 356
• C. 264
• D. 324

Answer 1

Answer:

D. 324

The marks of A = 62% more than B A = B + 62B/100 ⇒ A = 1.62B The marks of A – 24 = 150% of the marks of B. ⇒ A – 24 = (150/100) × B ⇒ 1.62B – 24 = 1.5B ⇒ 0.12B = 24 ⇒ B = 200 The marks of A = 1.62B ⇒ 1.62 × 200 = 324