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The moment of inertia of a solid cylinder of mass 'm', radius 'R' and length l' about the longitudinal axis or polar axis is-

AmR22\frac {mR^2}{2}

BmR24\frac {mR^2}{4}

CmR28\frac {mR^2}{8}

DmR26\frac {mR^2}{6}

Answer:

mR22\frac {mR^2}{2}

Read Explanation:

The moment of inertia of a solid cylinder of mass 'm', radius 'R' and length 'l' about the longitudinal axis is mR22\frac{m R ^ 2}{ 2} The moment of inertia of a body is the sum of the product of the masses of the particles and the square of their respective distances from the axis of rotation.

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