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The number of red, blue, and green marbles in a bag is in the ratio 3: 4: 6. If 20 red marbles, 15 blue marbles, and an unknown number of green marbles are added to the bag, the ratio of red, blue, and green marbles becomes 4: 5: 7. Determine the number of green marbles added.

A3

B5

C7

D9

Answer:

B. 5

Read Explanation:

Let the original numbers be in ratio (3:4:6):

So,

  • Red = (3x)

  • Blue = (4x)

  • Green = (6x)

After adding:

  • Red = (3x + 20)

  • Blue = (4x + 15)

  • Green = (6x + g) (where (g) is added green marbles)

New ratio is (4:5:7), so:

3x+204=4x+155=6x+g7\frac{3x+20}{4} = \frac{4x+15}{5} = \frac{6x+g}{7}

Step 1: Use first two ratios

3x+204=4x+155\frac{3x+20}{4} = \frac{4x+15}{5}

Cross multiply:

5(3x+20)=4(4x+15)5(3x+20) = 4(4x+15)
15x+100=16x+6015x + 100 = 16x + 60
100 - 60 = 16x - 15x
40 = x

Step 2: Find green marbles added

Original green:
6x=6×40=2406x = 6 \times 40 = 240
New green:

6x+g7=240+g7\frac{6x + g}{7} = \frac{240 + g}{7}

Use equality with red:
3x+204=120+204=1404=35\frac{3x+20}{4} = \frac{120+20}{4} = \frac{140}{4} = 35

So:
240+g7=35\frac{240 + g}{7} = 35
240+g=245240 + g = 245
g = 5

Final Answer:

=5


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