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The parallel sides of a trapezium are in a ratio 2 : 3 and their shortest distance is 12 cm. If the area of the trapezium is 480 sq.cm., the longer of the parallel sides is of length :

A56 cm

B36 cm

C42 cm

D48 cm

Answer:

D. 48 cm

Read Explanation:

.Let Sides of the trapezium be 2x and 3x cm

12(2x+3x)×12=480\frac{1}{2}(2x+3x)\times{12}=480

5x=48065x=\frac{480}{6}

x=805=16x=\frac{80}{5}=16

Larger Side =16×3=48cm= 16\times{3}=48cm


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