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The present ratio of age of two brothers is 5 : 4. If the ratio of their age become 11 : 9 after 3 years then what is the present age of the younger brother?

A25

B30

C18

D24

Answer:

D. 24

Read Explanation:

Let present age of younger brother be 'x' years Present age of elder brother be 'y' years ⇒ The ratio of the present ages of two brother is 5 : 4 ⇒ x : y = 5 : 4 ⇒ 4x = 5y x=5y/4 After 3 years , x : y = 11 : 9 ⇒(x + 3)/(y + 3) = 11 : 9 ⇒ 9x + 27 = 11y + 33 ⇒ 9x = 11y + 6 9 × 5/4y = 11y + 6 ⇒(45/4)y - 11y = 6 ⇒ y = 24


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