The present ratio of age of two brothers is 5 : 4. If the ratio of their age become 11 : 9 after 3 years then what is the present age of the younger brother?
A25
B30
C18
D24
Answer:
D. 24
Read Explanation:
Let present age of younger brother be 'x' years
Present age of elder brother be 'y' years
⇒ The ratio of the present ages of two brother is 5 : 4
⇒ x : y = 5 : 4
⇒ 4x = 5y
x=5y/4
After 3 years , x : y = 11 : 9
⇒(x + 3)/(y + 3) = 11 : 9
⇒ 9x + 27 = 11y + 33
⇒ 9x = 11y + 6
9 × 5/4y = 11y + 6
⇒(45/4)y - 11y = 6
⇒ y = 24