A9 : 10
B12 : 15
C11 : 10
D3 : 4
Answer:
C. 11 : 10
Read Explanation:
Solution:
Given:
The ratio of sprit and water = 2 : 5
Formula used:
If the volume is increased by a%, then the new volume will be [100(100+a)]×Initialvolume
Calculation:
Let an amount of sprit and water be 2 x and 5 x respectively and also let y liter is added to sprit.
Total volume = 2 x + 5 x
⇒ Total volume = 7 x
After adding y liter, new volume = 7 x + y
According to the question, the new volume of a solution is increased by 50% after adding sprit only.
⇒ The new volume of a solution =[100(100+50)]×7x
⇒ 7x+y=[100150]×7x
⇒ 7 x + y = 10.5 x
⇒ 10.5 x – 7 x = y
⇒ 3.5 x = y
⇒ yx=3.51
The resultant ratio of sprit and water =5x(2x+y)
⇒ The resultant ratio of sprit and water =(5x2x)+5xy
⇒ The resultant ratio of sprit and water =52+53.5
⇒ The resultant ratio of sprit and water =5(2+3.5)
⇒ The resultant ratio of sprit and water =55.5
⇒ The resultant ratio of sprit and water =1011
∴ The resultant ratio of sprit and water is 1011
Alternate Method
Ratio of sprit and water = 2 : 5
Let the Sprit and water be 20x and 50x respectively.
Initial total volume = (20x + 50x) = 70x
Then, the volume of solution increased by 50% means,
⇒ (70x)×{50%}= 35x
⇒ 70x + 35x = 105x
According to the question,
Only sprit is added in the solution and water is same as before.
New total volume = 105x
New sprit solution = new total volume - initial water solution
⇒ new sprit solution = 105x - 50x = 55x
Resultant ratio of sprit and water = 55x : 50x
⇒ Ratio = 11 : 10
∴ The resultant ratio of sprit and water is 11 : 10