Question

The ratio of the length of the parallel sides of a trapezium is 3:2. The shortest distance between them is 15 cm. If the area of the trapezium is 450 cm2, the sum of the length of the parallel sides is

• A. 15 cm
• B. 36 cm
• C. 42 cm
• D. 60 cm

Answer 1

Answer:

D. 60 cm

.Area of the trapezium =$\frac{1}{2}\times$(sumof parallel sides) × altitude

$450=\frac{1}{2}(3x+2x)\times{15}$

$5x=\frac{450\times{2}}{15}=60cm$