Question

The ratio of the present ages of a man and his wife is 7: 6. After 6 years, this ratio will be 8: 7. If, at the time of marriage, the ratio of their ages was 4: 3, then how many years ago from now did they get married?

• A. 15 years
• B. 13 years
• C. 18 years
• D. 16 years

Answer 1

Answer:

C. 18 years

$\frac{7x+6}{6x+6}=\frac87$

$49x+42=48x+48$

$x=6$

present age is

$7\times 6=42$

$6\times 6=36$

y years back the Marriage

$\frac{42-y}{36-y}=\frac43$

$126-3x=144-4x$

$x=18$