Question

The value of $[(0.111)^3+(0.222)^3-(0.333)^3+(0.333)^2\times(0.222)]^2=$

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

Answer:

A. 0

If $a^3 +b^3 +c^3 = 3abc$

then, $a+b+c=0$

a = 0.111, b = 0.222, c = -0.333

$(0.111)^3+(0.222)^3+(-0.333)^3-0.333\times0.333\times0.222$

$=(0.111)^3+(0.222)^3+(-0.333)^3-3\times0.111\times0.333\times0.222$

$\implies0.111+0.222-0.333=0$