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The greatest number of 3 digits which is divisible by 5, 15, 21 and 49 is :

A715

B765

C785

D735

Answer:

D. 735

Read Explanation:

735 is the greatest 3-digit number divisible by 5, 15, 21, and 49.

  1. Find the LCM of the given numbers: 5, 15, 21, and 49.

    • Prime factorization of 5 = 515^1

    • Prime factorization of 15 = 31×513^1 \times 5^1

    • Prime factorization of 21 = 31×713^1 \times 7^1

    • Prime factorization of 49 = 727^2

    • LCM=31×51×72=3×5×49=735\text{LCM} = 3^1 \times 5^1 \times 7^2 = 3 \times 5 \times 49 = \mathbf{735}

  2. Find the greatest 3-digit multiple:

    • The greatest 3-digit number is 999.

    • Divide 999 by the LCM (735): 999÷735=1 with a remainder of 264999 \div 735 = 1 \text{ with a remainder of } 264.

    • Subtract the remainder from 999: 999−264=735999 - 264 = \mathbf{735}.


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