Question

The value of $\frac{2tan60}{1+tan^260}=$

• A. sin 30°
• B. sin 60°
• C. cos 60°
• D. tan 60°

Answer 1

Answer:

B. sin 60°

$\frac{2tan60}{1+tan^260}=\frac{2 \sqrt 3}{1+(\sqrt 3)^2}=\frac{2 \sqrt 3}{4}=\frac{\sqrt3}{2}= sin 60°$