App Logo

No.1 PSC Learning App

1M+ Downloads
The weight of Ayush and Abhishek are in the ratio of 8 ∶ 5. Abhishek's weight increases by 40 percent and the total weight of Ayush and Abhishek both increase by 60 percent. If the total weight becomes 104 kg, then what is the weight of Ayush after the increment?

A60 kg

B75 kg

C69 kg

D72 kg

Answer:

C. 69 kg

Read Explanation:

Given:

The weight of Ayush and Abhishek is in the ratio of 8:5.

Abhishek's weight increased by 40%.

The total weight of Ayush and Abhishek both increased by 60%.

The total weight becomes 104 kg.

Formulas:

Increase in weight = Originalweight×Percentageincrease100Original weight\times\frac{Percentage increase}{100}

Solution:

Let's assume:

The weight of Ayush = 8x

The weight of Abhishek = 5x

Abhishek's weight after the increase:

Increase in weight = 5×401005\times\frac{40}{100}

Increase in weight = 2x

New weight of Abhishek = 5x + 2x = 7x

Total weight of Ayush and Abhishek after the increase:

Increase in weight = (8x +5x)×60100\times\frac{60}{100}

Increase in weight = 13x×60100\times\frac{60}{100}

Increase in weight = 7.8x

Total weight after the increase:

Total weight = 8x + 5x + 7.8x

Total weight = 20.8x

Given that the total weight becomes 104 kg, we can set up the equation:

20.8x = 104

To solve for x, we divide both sides of the equation by 20.8:

x = 10420.8\frac{104}{20.8}

x = 5

Now that we know x, we can find the weight of Abhishek after the increment:

Weight of Abhishek = 7x

Weight of Abhishek = 7×57\times{5}

Weight of Abhishek = 35 kg

The total weight after the increment is 104.

So, the weight of Ayush after the increment is 104 - 35 = 69

Therefore, the weight of Ayush after the increment is 69 kg.


Related Questions:

Investments made by A, B and C in a craft business is Rs.47,000. If A invest Rs.7,000 more than B and B invest Rs.5,000 more than C, then find the amount C gets out of the total profit Rs.4700.
If the ratio of the first to second number is 3 : 4 and that of the second to the third number is 8 : 5, and sum of three numbers is 190 then the third number is:
Two bottles A and B contain diluted acid. In bottle A, the amount of water is double the amount of acid while in bottle B, the amount of acid is 3 times that of water. How much mixture(in litres) should be taken from each bottle A and B respectively in order to prepare 5 liters diluted acid containing an equal amount of acid and water?
The sum of two numbers is 40 one number is 10 more than the other what are the numbers?
The mean proportional between 36 and 121 is equal to: