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There are six students, P, Q, R, S, T and U who have a different number of pens - 2, 4, 5, 7, 9 and 12 (not necessarily in the same order). The number of pens Q has is a prime number. U has 2 more pens than Q. The number of pens R has is a multiple of 4 but not a multiple of 3. P has fewer pens than Q but has more pens than S. Who has the highest number of pens?

AP

BQ

CS

DT

Answer:

D. T

Read Explanation:

Students: P, Q, R, S, T and U.

No. of pens: 2, 4, 5, 7, 9 and 12 (not necessarily in the same order).

1) The number of pens Q has is a prime number.

Student

No. of Pen

P

 

Q

2/5/7

R

 

S

 

T

 

U

 

 

2) U has 2 more pens than Q.

Student

No. of Pen

P

 

Q

2/5/7

R

 

S

 

T

 

U

4/ 7/ 9

 

3) The number of pens R has is a multiple of 4 but not a multiple of 3.

(So, R has 4 pens only.)

Student

No. of Pen

P

 

Q

5/7

R

4

S

 

T

 

U

7/ 9

 

4) P has fewer pens than Q but has more pens than S.

(P cannot have 2 pens as S has fewer pens than P.

So, P has 5 pens and S has 2 pens.)

Student

No. of Pen

P

5

Q

7

R

4

S

2

T

 

U

9

 

(So, T has 12 pens.)

Final arrangement:

Student

No. of Pen

P

5

Q

7

R

4

S

2

T

12

U

9

 

Hence, T has the highest number of pens.


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