Question

Three years ago father’s age was 7 times his son's age. Three years hence the father’s age would be four times that of his son. What are the present ages of father and the son?

• A. 42 years, 9 years
• B. 45 years, 9 years
• C. 35 years, 8 years
• D. 48 years, 14 years

Answer 1

Answer:

B. 45 years, 9 years

Let the present age of father and son be m and n years respectively. (m – 3) = 7(n – 3) m – 3 = 7n – 21 7n – m = 18…................. (1) (m + 3) = 4(n + 3) m + 3 = 4n + 12 m – 4n = 9….................... (2) From Equation (1) and Equation (2); 3n = 27 n = 9 m = 45