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Two circles with radii r₁ and r₂ touch each other externally. If the length of their direct common tangent is T, which of the following is the correct relationship between T, r₁, and r₂ ?

AT= r₁ + r₂

BT= 2( r₁ + r₂)

CT= 2√r₁r₂

DT= r₁² + r₂²

Answer:

C. T= 2√r₁r₂

Read Explanation:

If two circles of radii (r_1) and (r_2) touch externally, then the distance between their centres is

d=r1+r2.d=r_1+r_2.

The length (T) of the direct (external) common tangent is given by

T=d2−(r1−r2)2.T=\sqrt{d^2-(r_1-r_2)^2}.

Substituting(d=r1+r2): (d=r_1+r_2):


T=(r1+r2)2−(r1−r2)2.T=\sqrt{(r_1+r_2)^2-(r_1-r_2)^2}.

Using the identity

(a+b)2−(a−b)2=4ab,(a+b)^2-(a-b)^2=4ab,

we get

T=4r1r2=2r1r2.T=\sqrt{4r_1r_2}=2\sqrt{r_1r_2}.

Answer:

T=2r1r2\boxed{T=2\sqrt{r_1r_2}}

or equivalently,

T2=4r1r2.\boxed{T^2=4r_1r_2.}


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