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Two containers of the same volume are 40% and 50% full of water, respectively. They are then filled completely with milk. If the contents of both containers are mixed in a larger vessel, what is the percentage of milk in the final mixture?

A45%

B60%

C55%

D50%

Answer:

C. 55%

Read Explanation:

Let the volume of each container be 100 units.

Container 1

  • Water = 40 units

  • Milk = 60 units

Container 2

  • Water = 50 units

  • Milk = 50 units

After mixing

Total volume:

100 + 100 = 200
Total milk:

60 + 50 = 110
Percentage of milk in the final mixture:

110200×100=55%\frac{110}{200}\times 100 = 55\%

Percentage of milk in the final mixture = 55%.


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