Question

Two numbers are less than the third number by 40% and 50% respectively. By how much percent is the first number greater than the second number?

• A. 16.66%
• B. 10%
• C. 20%
• D. 34%

Answer 1

Answer:

C. 20%

Third number be X.





first number =  X × (60%)





⇒ X × (60/100)





⇒ X × (3/5)





⇒ 3X/5





second number = X × (50%)





⇒ X × (50/100)





⇒ X × (1/2)





⇒ X/2





Percentage difference ={(3X/5 - X/2)/X/2} × 100





= {(X/10)/(X/2)} × 100





⇒ (2/10) × 100





⇒ 20%
Alternate method

Let the third number be 100.





first number = 100 - 40





⇒ 60





second number = 100 - 50





⇒ 50





Increase in number = 60 - 50





⇒ 10





Percentage Difference = {(Increase in value)/Original value} × 100





⇒ (10/50) × 100





⇒ 20%