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Two successive discounts of 30% and 20% was offered on food items. A man paid ₹840 for the food item. The bill amount of food item (in ₹) is:

A2000

B1200

C1800

D1500

Answer:

D. 1500

Read Explanation:

Let the original bill amount be ₹x.

Two successive discounts are given:
First discount = 30%
Second discount = 20

Step 1: Apply first discount (30%)

After 30% discount, price becomes:
x×(1−0.30)=0.7xx \times (1 - 0.30) = 0.7x

Step 2: Apply second discount (20%) on the reduced price

0.7x×(1−0.20)=0.7x×0.8=0.56x0.7x \times (1 - 0.20) = 0.7x \times 0.8 = 0.56x

So, the final price paid = 0.56x

Given:
0.56x=8400.56x = 840
x=8400.56x = \frac{840}{0.56}
x = 1500

Original bill amount = ₹1500


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