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Two trians X and Y start at the same time, X from station A to B and Y from B to A. After passing each other, X and Y take 8258\frac{2}{5} hours and 4274\frac{2}{7} hours, respectively, to reach their respective destinations. If the speed of X is 50 km/h, then what is the speed (in km/h) of Y?

A84

B56

C63

D70

Answer:

D. 70

Read Explanation:

Solution:

Given:

After passing each other, X and Y take 825and427hours8\frac{2}{5}and4\frac{2}{7}hours

The speed of X is 50 km/h

Concept Used:

If two trains start at the same time with speeds x km/h and y km/h and after meeting they reach their destination in t1 hours and t2 hours then the relation between speed and time is xy=t2t1\frac{x}{y}=\sqrt{\frac{t2}{t1}}

Calculation:

Here x = 50 km/h

t1=825=425hourst1=8\frac{2}{5}=\frac{42}{5}hours

t2=427=307hourst2=4\frac{2}{7}=\frac{30}{7}hours

Let, the speed of the train Y be a km/h

Accordingly,

50a=307425{50 \over a} = {\sqrt{{30 \over 7} \over {42 \over 5}}}

50a=30×57×42{{50} \over a} = {\sqrt{{30 \times 5} \over {7 \times 42}}}

50a=5×57×7{50 \over a} = \sqrt {5 \times 5 \over 7 \times 7}

50a=57\frac{50}{a}=\frac{5}{7}

⇒ a = 70

∴ The speed of the train Y is 70 km/hr.


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