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Varun invests a sum of ₹5400 and Ashish invests a sum of ₹9400 at the same rate of simple interest per annum. If, at the end of 3 years, Ashish gets ₹960 more interest than Varun, then find the rate of interest per annum (in percentage).

A8

B10

C7

D6

Answer:

A. 8

Read Explanation:

Let rate = (r%) per annum.

Simple Interest:

SI=P×r×t100SI = \frac{P \times r \times t}{100}

Time (t = 3) years

Difference in interests:

SIAshish−SIVarun=960SI_{Ashish} - SI_{Varun} = 960


9400⋅r⋅3100−5400⋅r⋅3100=960\frac{9400 \cdot r \cdot 3}{100} - \frac{5400 \cdot r \cdot 3}{100} = 960

Take common terms:
3r100(9400−5400)=960\frac{3r}{100}(9400 - 5400) = 960

3r100⋅4000=960\frac{3r}{100} \cdot 4000 = 960

120r = 960

r=8r = 8

Final Answer: 8% per annum


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