AMonday
BSaturday
CFriday
DSunday
Answer:
D. Sunday
Read Explanation:
Solution:
The pattern followed here is:
No. of Odd days.
Every ordinary year contains = 1 Odd day.
Every leap year contains = 2 Odd days.
No. of Odd days in centuries.
Years | No. of Odd days |
100 Years | 5 |
200 Years | 3 |
300 Years | 1 |
400 Years | 0 |
Code for weekdays.
No. of Odd days | Day |
0 | Sunday |
1 | Monday |
2 | Tuesday |
3 | Wednesday |
4 | Thursday |
5 | Friday |
6 | Saturday |
We find the Odd days = (nearest leap century year + the nearest century year + completing year) = 2000 + 19 year + year 2020
⇒ In 19 year = 4 leap year & 15 Ordinary year
⇒ 4 leap year = 8 odd days = 1 Odd day
⇒ 15 Ordinary year = 15 Odd days = 1 Odd day
⇒ In 2000 year the od days = 0 Odd day
⇒ Number of Odd days 1st Jan to 1 March = 31 + 29 + 1 = 61 ÷ 7 = 5 Odd days
Addition of all Odd days.
⇒ 0 + 1 + 1 + 5 = 7 Days = 0 Odd day.
0 is the code of Sunday.
Hence, the correct answer is "Sunday".