What do we get on simplifying the expression xx+1+x+1x−1x(x+1)\frac{x}{x+1}+\frac{x+1}{x}-\frac{1}{x(x+1)}x+1x+xx+1−x(x+1)1 ? Ax/2BxC1/2D2Answer: D. 2 Read Explanation: xx+1+x+1x−1x(x+1)\frac{x}{x+1}+\frac{x+1}{x}-\frac{1}{x(x+1)}x+1x+xx+1−x(x+1)1x×xx(x+1+(x+1)(x+1)x(x+1)−1x(x+1)\frac{x\times x}{x(x+1}+\frac{(x+1)(x+1)}{x(x+1)}-\frac{1}{x(x+1)}x(x+1x×x+x(x+1)(x+1)(x+1)−x(x+1)1x2+(x+1)2−1x(x+1)\frac{x^2+(x+1)^2-1}{x(x+1)}x(x+1)x2+(x+1)2−1x2+x2+2x+1−1x(x+1)\frac{x^2+x^2+2x+1-1}{x(x+1)}x(x+1)x2+x2+2x+1−1x(x+x+2)x(x+1)\frac{x(x+x+2)}{x(x+1)}x(x+1)x(x+x+2)2x+2x+1\frac{2x+2}{x+1}x+12x+22(x+1)x+12(x+1){x+1}2(x+1)x+1=2 Read more in App