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What do we get on simplifying the expression xx+1+x+1x1x(x+1)\frac{x}{x+1}+\frac{x+1}{x}-\frac{1}{x(x+1)} ?

Ax/2

Bx

C1/2

D2

Answer:

D. 2

Read Explanation:

xx+1+x+1x1x(x+1)\frac{x}{x+1}+\frac{x+1}{x}-\frac{1}{x(x+1)}

x×xx(x+1+(x+1)(x+1)x(x+1)1x(x+1)\frac{x\times x}{x(x+1}+\frac{(x+1)(x+1)}{x(x+1)}-\frac{1}{x(x+1)}

x2+(x+1)21x(x+1)\frac{x^2+(x+1)^2-1}{x(x+1)}

x2+x2+2x+11x(x+1)\frac{x^2+x^2+2x+1-1}{x(x+1)}

x(x+x+2)x(x+1)\frac{x(x+x+2)}{x(x+1)}

2x+2x+1\frac{2x+2}{x+1}

2(x+1)x+12(x+1){x+1}

=2


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