What is the area of an equilateral triangle with side length of 4 cm?
A$\frac{\sqrt{3}}{4} \text{ cm}^2$
B$2\sqrt{3} \text{ cm}^2$
C$4\sqrt{3} \text{ cm}^2$
D$16\sqrt{3} \text{ cm}^2$
A$\frac{\sqrt{3}}{4} \text{ cm}^2$
B$2\sqrt{3} \text{ cm}^2$
C$4\sqrt{3} \text{ cm}^2$
D$16\sqrt{3} \text{ cm}^2$
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If , then determine the value of the ?
In the figure ABCD is a square. The length of its diagonal is 4√2 centimetres. The area of the square is :