What is the area of an equilateral triangle with side length of 4 cm?
A$\frac{\sqrt{3}}{4} \text{ cm}^2$
B$2\sqrt{3} \text{ cm}^2$
C$4\sqrt{3} \text{ cm}^2$
D$16\sqrt{3} \text{ cm}^2$
A$\frac{\sqrt{3}}{4} \text{ cm}^2$
B$2\sqrt{3} \text{ cm}^2$
C$4\sqrt{3} \text{ cm}^2$
D$16\sqrt{3} \text{ cm}^2$
Related Questions: