What is the greatest number of six digits, which when divided by each of 16, 24, 72 and 84, leaves the remainder 15?
A999981
B999951
C999963
D999915
Answer:
B. 999951
Read Explanation:
L.C.M ( 16,24,72 ,84) = 1008
dividing 999999/1008 = 63 (remainder)
999999 - 63 = 999936
This number 999936 is completely divisible by 16,24,72 and 84
15 is the remainder on dividing by them
required number = 999936 + 15 = 999951
