Question

What is the least number added to 2488 so that it is completely divisible by 3,4,5 and 6?

• A. 32
• B. 34
• C. 42
• D. 28

Answer 1

Answer:

A. 32

if the number is completely divisible by 3,4,5,6 the last digit should be "0"

so we can eliminate the b&d option

then the two numbers are

$2488+32=2520$ and $2488+42=2530$

while checking the divisibility of 3

the sum of these numbers should be divisible by 3

$2520=2+5+2+0=9$ it is divisible by 3

$2530=2+5+3+0=10$= it is not divisible by 3

so the option is "a"