Challenger App

No.1 PSC Learning App

1M+ Downloads

What is the value of (3/5)2×(5/7)23/5)3×(7/5)2=?\frac{(3/5)^2\times(5/7)^{-2}}{3/5)^3\times(7/5)^2}=?

A3/5

B7/3

C3/7

D5/3

Answer:

D. 5/3

Read Explanation:

(3/5)2×(5/7)2(3/5)3×(7/5)2\frac{(3/5)^2\times(5/7)^{-2}}{(3/5)^3\times(7/5)^2}

=(3/5)2×(5/7)2×(5/3)3×(5/7)2=(3/5)^2\times(5/7)^{-2}\times(5/3)^3\times(5/7)^2

=5/3=5/3


Related Questions:

54×5357=?\frac{5^4 × 5^3}{5^7}=?

52.7 / .......= 0.527
5/6.625 = 0.7547 ആയാൽ 5/6625 എത്ര ?
0.45 എന്ന ദശാംശ സംഖ്യയുടെ ഭിന്ന സംഖ്യാ രൂപം ?

Simplify:
(212+3.6)1.9(2\frac{1}{2}+3.6)-1.9