Challenger App

No.1 PSC Learning App

1M+ Downloads

What is to be added to 2362^{36} to get 2372^{37}?

A2

B2362^{36}

C262^{6}

D2372^{37}

Answer:

2362^{36}

Read Explanation:

236+x=2372^{36}+x=2^{37}

x=237236x=2^{37}-2^{36}

x=236[21]x=2^{36}[2-1]

x=236×1=236x=2^{36}\times1=2^{36}

To check it is correct,

236+2362^{36}+2^{36}

=236[1+1]=2^{36}[1+1]

=236×2=2^{36}\times2

=236+1=2^{36+1}

=237=2^{37}


Related Questions:

62×104×15326×35×56= \frac {6^2 \times 10^4 \times 15^3} {2^6 \times 3^5 \times 5^6} =\rule{1cm}{0.1 pt}

image.png
5x1×53×52=31255^{x-1} \times 5^3 \times 5^2 = 3125 എങ്കിൽ 'x' ന്റെ വില
2102^{10} നോട് എത്ര കൂട്ടിയാൽ 2112^{11} കിട്ടും?

(0.04)(1.5)(0.04)^{(-1.5)}എത്ര?