Question

What time (in seconds) is required for a 496 m long train to cross a 664 m long tunnel, if the train travels at a speed of 18 km/h?

• A. 232
• B. 230
• C. 236
• D. 224

Answer 1

Answer:

A. 232

To cross a tunnel, the train must cover its own length + tunnel length.

Total distance

$496 + 664 = 1160 \text{ m}$
Convert speed

$18 \text{ km/h} = 18 \times \frac{5}{18} = 5 \text{ m/s}$
Time

$\text{Time} = \frac{\text{Distance}}{\text{Speed}} = \frac{1160}{5} = 232 \text{ seconds}$