Question

What will be the strain energy stored in the metallic bar of cross sectional area of 2 cm and gauge length of 10 cm if it stretches 0.002 cm under the load of 12 kN?

• A. 10 N-cm
• B. 12 N-cm
• C. 14 N-cm
• D. 16 N-cm

Answer 1

Answer:

B. 12 N-cm

Given: $\delta = 0.002cm$ $P = 12kN = 12000N$ The strain energy stored in the metallic bar, $E =\frac12 \times P\times \delta =\frac12 \times 12000 \times 0.002 = 12N-cm$