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Strain energy stored in a prismatic bar suspended from one end due to its own weight (elastic behavior) [x = specific weight of material, A = cross-sectional area, L = length of bar]

AU=x2A2L26EU =\frac{x^2A^2L^2}{6E}

BU=xAL36EU =\frac{xAL^3}{6E}

CU=x2AL33EU =\frac{x^2AL^3}{3E}

DU=x2AL36EU =\frac{x^2AL^3}{6E}

Answer:

U=x2AL36EU =\frac{x^2AL^3}{6E}

Read Explanation:

The strain energy stored in a prismatic bar clue to its own weight is given by $U =\frac{x^2AL^3}{6E}$. Strain energy is the energy absorbed by the member when work done by the load deforms that member. For a prismatic bar, the axial load due to its own weight is $xAL$.

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