Interchanging + and ÷ means: every ÷ becomes +, and every +$becomes\div.</p></li><li><pdata−pxy="true"style="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px;">Interchanging<b>-</b>and<b>\times</b>means:every-becomes\times,andevery\timesbecomes-.</p></li></ul><hr><h2style="color:rgb(0,0,0);"><b><spanstyle="font−size:18px;">1.ApplytheInterchanges</span></b></h2><pdata−pxy="true"style="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px;">Rewritingtheequationwiththesubstitutedmathematicalsymbolsyields:<br>23 + 16 \div 8 \times 3 - 21 = ?</p><h2style="color:rgb(0,0,0);"><b><spanstyle="font−size:18px;">2.SolveUsingBODMASRules</span></b></h2><pdata−pxy="true"style="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px;">Weevaluateoperationsinorder:<b>D</b>ivision\rightarrow<b>M</b>ultiplication\rightarrow<b>A</b>ddition\rightarrow<b>S</b>ubtraction.</p><pstyle="color:rgb(0,0,0);"></p><ulstyle="color:rgb(0,0,0);"><li><pdata−pxy="true"style="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px;"><b>Step2a(Division):</b>Solve16 \div 8<br>16 \div 8 = 2<br><em>Equationupdatesto:</em>23 + 2 \times 3 - 21 = ?</p></li><li><pdata−pxy="true"style="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px;"><b>Step2b(Multiplication):</b>Solve2 \times 3<br>2 \times 3 = 6<br><em>Equationupdatesto:</em>23 + 6 - 21 = ?</p></li><li><pdata−pxy="true"style="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px;"><b>Step2c(Addition):</b>Solve23 + 6<br>23 + 6 = 29<br><em>Equationupdatesto:</em>29 - 21 = ?</p></li><li><pdata−pxy="true"style="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px;"><b>Step2d(Subtraction):</b>Solve29 - 21<br>29 - 21 = 8$