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When both ends of column are pinned or hinged, buckling load equation is given by

Aπ2EIl2\frac{\pi^2EI}{l^2}

Bπ3EIl3\frac{\pi^3EI}{l^3}

Cπ2EIl3\frac{\pi^2EI}{l^3}

Dπ2EIl4\frac{\pi^2EI}{l^4}

Answer:

π2EIl2\frac{\pi^2EI}{l^2}

Read Explanation:

End conditions

LeL_e

Buckling load

Both ends Hinged

Le=LL_e=L

Pb=π2EIL2P_b=\frac{\pi^2EI}{L^2}

Both ends Fixed

Le=L2L_e=\frac L2

Pb=4π2EIL2P_b=\frac{4\pi^2EI}{L^2}

One end fixed and other end is free

Le=2LL_e=2L

Pb=π2EI4L2P_b=\frac{\pi^2EI}{4L^2}

One end fixed and other end is hinged

Le=L2L_e=\frac {L}{\sqrt2}

Pb=2π2EIL2P_b=\frac{2\pi^2EI}{L^2}


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