App Logo

No.1 PSC Learning App

1M+ Downloads
Which of the following is true for ideal column compressed by an axial load (P)?

AColumn will be in unstable equilibrium if P < P critical

BColumn will buckle if P < Pcritical

CColumn will be in stable equilibrium if P < P critical

DColumn will be in stable equilibrium if P > Pcritical

Answer:

C. Column will be in stable equilibrium if P < P critical

Read Explanation:

The maximum load a column can bear before buckling or having lateral displacement is known as buckling or crippling load. The column will be in stable equilibrium if the load is less than the critical load. Euler's column formulas can be used to analyze load columns. The formula is P=n2π2EIL2P =\frac{n ^ 2 \pi ^ 2 EI}{L ^ 2} where n is the end condition factor, L is the effective length, E is the modulus of elasticity, and I is the moment of inertia.

Related Questions:

Steel column pinned at both ends has a modulus of elasticity E=2×105N/mm2E = 2 \times 10^5 N/mm^2, moment of inertia I = 90000mm, L = 1.75 m, value of Euler's critical load will be
For a column of length (L) and flexural rigidity (El) which has one end fixed and other end free, the expression for critical load is given as -
For a long slender column of uniform cross section, the ratio of critical buckling load for the case with both ends closed to the case with both ends hinged is
Column A has both its ends fixed, and column B has one end fixed and the other end free. The ratio of the buckling load of column A to that of column B is:
Euler's formula is not valid for mild steel column when slenderness ratio is