A5/4
B3/7
C2/6
D7/8
Answer:
Related Questions:
(1−12)(1−13)(1−14)(1−15) (1- \frac{1}{2})(1- \frac{1}{3})(1- \frac{1}{4})(1- \frac{1}{5})(1−21)(1−31)(1−41)(1−51) = ____
x=2, y= -2 ആയാൽ Xx+Yy=X^x+Y^y=Xx+Yy=
32+23÷32−12=\frac{3}{2} + \frac{2}{3}\div \frac{3}{2} - \frac{1}{2} = 23+32÷23−21=
