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Which of the following letter-number clusters will replace the question mark (?) in the given series to make it logically complete? HDX 7, MIC 16, RNH 34, WSM 70, BXR 142, ?

AHCW 286

BGCW 286

CGCW 268

DGCL 286

Answer:

B. GCW 286

Read Explanation:

The letter-number cluster that will replace the question mark (?) is GCW 286.

## 1. The Number Pattern

* 7→167 \rightarrow 16 (7×2)+2=16(7 \times 2) + 2 = 16

* 16→3416 \rightarrow 34 (16×2)+2=34(16 \times 2) + 2 = 34

* 34→7034 \rightarrow 70 (34×2)+2=70(34 \times 2) + 2 = 70

* 70→14270 \rightarrow 142 (70×2)+2=142(70 \times 2) + 2 = 142

* 142→286142 \rightarrow \mathbf{286} (142×2)+2=286(142 \times 2) + 2 = \mathbf{286}

*

## 2. The Letter Pattern

Let's analyze the positions of the letters in the English alphabet (A=1,B=2,…,Z=26A=1, B=2, \dots, Z=26):

*

* First Letter: H →\rightarrow M →\rightarrow R →\rightarrow W →\rightarrow B →\rightarrow ?

* H(8)+5=M(13)H (8) + 5 = M (13)

* M(13)+5=R(18)M (13) + 5 = R (18)

* R(18)+5=W(23)R (18) + 5 = W (23)

* W(23)+5=B(28→2)W (23) + 5 = B (28 \rightarrow 2)

* B(2)+5=G(7)B (2) + 5 = \mathbf{G (7)}

* Second Letter: D →\rightarrow I →\rightarrow N →\rightarrow S →\rightarrow X →\rightarrow ?

* D(4)+5=I(9)D (4) + 5 = I (9)

* I(9)+5=N(14)I (9) + 5 = N (14)

* N(14)+5=S(19)N (14) + 5 = S (19)

* S(19)+5=X(24)S (19) + 5 = X (24)

* X(24)+5=C(29→3)X (24) + 5 = \mathbf{C (29 \rightarrow 3)}

* Third Letter: X →\rightarrow C →\rightarrow H →\rightarrow M →\rightarrow R →\rightarrow ?

* X(24)+5=C(29→3)X (24) + 5 = C (29 \rightarrow 3)

* C(3)+5=H(8)C (3) + 5 = H (8)

* H(8)+5=M(13)H (8) + 5 = M (13)

* M(13)+5=R(18)M (13) + 5 = R (18)

* R(18)+5=W(23)R (18) + 5 = \mathbf{W (23)}

Combining the missing letter cluster (GCW) with the missing number (286) gives the next term: GCW 286.


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